16t^2-35t=16

Solution for 16t^2-35t=16 equation:

16t^2-35t=16

We move all terms to the left:

16t^2-35t-(16)=0

a = 16; b = -35; c = -16;
Δ = b2-4ac
Δ = -352-4·16·(-16)
Δ = 2249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{2249}}{2*16}=\frac{35-\sqrt{2249}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{2249}}{2*16}=\frac{35+\sqrt{2249}}{32}
$